A mixture is prepared by mixing $1.560$ mole Toluene and $3.50$ mole Benzene. If the vapor pressure of pure Benzene and Toluene are $40.55 ~ \text {kPa}$ and$\text { 20.24 kPa,}$ respectively at $\mathrm {0^°C,}$ then the total vapor pressure of the mixing will be.